Work Energy Theorem

A satellite of mass $m$, initially at rest on the earth, is launched into a circular orbit at a height equal to the radius of the earth. The minimum energy required is

If the momentum of the body increases by $10\%$ then the increase in Kinetic energy of the body is

The block weighing $40 \mathrm{N}$ starts slipping on the track from a point $2 \mathrm{m}$ above the horizontal surface. It travels down a smooth, fixed and curved track $AB$ joined to a rough horizontal surface (see figure). The rough surface has a friction coefficient of $0.10$ with the block. The distance it moves on the rough surface is,

When mass and speed are doubled the $\mathrm{K}.\mathrm{E}.$ increases

An object of mass $100 \mathrm{g}$ is sliding under gravity from point $\mathrm{A}$ to point $\mathrm{B}$ on a frictionless slide from a height of $5 \mathrm{m}$, as shown in the figure. After what distance will the object stop on the following flat track beyond point $\mathrm{B}$. if the coefficient of kinetic friction between the flat track and the object is $0.5 ?$

A particle of mass $100 \mathrm{g}$ is thrown vertically upward with a speed of $5 {\mathrm{ms}}^{-1}$. The work done by the force of gravity during the time the particle goes up is

The $K\mathit{.}E\mathit{.}$ acquired by a mass $m$ in travelling a certain distance $d$, starting from rest, under the action of a constant force is directly proportional to:

A $16 \mathrm{kg}$ block moving on a frictionless horizontal surface with a velocity of $4 \raisebox{1ex}{$\mathrm{m}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{s}$}\right.$ compresses an ideal spring and comes to rest, if the force constant of the spring be $100 \raisebox{1ex}{$\mathrm{N}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{m}$}\right.$, then the spring is compressed by

Two masses of $1 \mathrm{g}$ and $4 \mathrm{g}$ are moving with equal kinetic energy. The ratio of the magnitude of their momenta is

Kinetic energy of a body can be increased more by _____.

A shell explodes in mid-air. It's total:

The displacement of particle of mass $5 \mathrm{kg}$ moving along straight line is given as $t=\sqrt{x}+2.$ The work done by the force in first $4 \mathrm{s}$ is

An air molecule of mass $5.0\times {10}^{-26} \mathrm{kg}$ and moving with a speed of $500 \mathrm{m} {\mathrm{s}}^{-1}$ has a kinetic energy of about $\left(e=1.6\times {10}^{-19} \mathrm{C}\right)$

A body of mass $2 \mathrm{kg}$ thrown vertically upward from the ground with a velocity of $8 \mathrm{m} {\mathrm{s}}^{-1}$ reaches a maximum height of $3 \mathrm{m}$. Magnitude of work done by the air resistance is (Acceleration due to gravity $=10 \mathrm{m} {\mathrm{s}}^{-2}$ )

A car of mass $2000 \mathrm{kg}$ is moving at a speed of $20 {\mathrm{ms}}^{-1}$ up an inclined plane making an angle $30°$ with the horizontal. At some point, the motor stops, and the car continues to move along the plane due to its initial velocity. If it is just able to reach the destination which is at a height of $10 \mathrm{m}$ above the point, calculate the work done against friction acting between the tyres of the car and the plane. (Assume $g=10 \mathrm{m} {\mathrm{s}}^{-2}$)

If the linear momentum is increased by $50\%$ then the kinetic energy will increase by

An object of mass $8 \mathrm{kg}$ moves along positive $X-$axis. When it passes through $X=0,$ a constant force directed along the negative $X-$axis begins to act on it. The kinetic energy of the object is found to be $0$ and $30 \mathrm{J}$ for $X=5 \mathrm{m}$ and $X=0 \mathrm{m}$ respectively. If the force continues to act further, then the object moves back along negative $X-$axis. The speed of the object when it reaches $X=-3 \mathrm{m}$